cron script -run every 2nd day of month except Monday


 
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# 1  
Old 10-23-2008
cron script -run every 2nd day of month except Monday

I know I can't schedule this in cron and would have to write a wrapper around my script and schedule it in cron ....but not sure how do to this?

How do I exclude Monday if the 2nd day of the month falls on a Monday?

Thanks.

I tried this:
0 0 2 * 0,2-6 command

And I know this doesnt work.

Thanks.



# 2  
Old 10-23-2008
Don't worry about stuff like that in cron. Simply have your script exit if today == 2nd of the month and today == Monday as well.

Code:
#!/bin/ksh

date "+%a %m" | read day dt
if [[ "$dt" = "02" && "$day" = "Mon" ]] ; then
    exit
fi

Then just submit it on the 2nd of every month. Or whenever needed.
# 3  
Old 10-23-2008
Thank you so much!
 
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