UNIX for Dummies Questions & Answers

Hi,

Can anyone help me with the text editing I need here. I have a file that contains the following lines for example: (line numbers are for illustration only)

1 Hello world fantasy.
2 Hello worldfuntastic.
3 Hello world wonderful.

I would like to get all those lines of text that contains the word "world" without anything after it. Meaning, I would like to have lines 1 and 3, line 2 should not be included because it contains "worldfuntastic", no space between.

1 Hello world fantasy.
3 Hello world wonderful

The problem is, there are some lines that use TAB to separate words like line 3. When I use grep "world " <filename>, this will get all lines of text with the word "world" and space after it but not those with TAB, i.e. the results would only be:
1 Hello world fantasy

line 3 is not included because "world" and "wonderful" are separated by TAB. Any suggestions, please?

Code:

egrep "[[:space:]]world[[:space:]]" infile

The [[:space:]] works with any kind and number of concatenated spaces, wether it's blanks or tabs etc.

I tried with egrep [[:space:]]....but i think it doesn't work:

I just tried with this grep " world " infile....(include the spaces between the before and after the word "world".

if you want to grab whole words, the basic logic is to go through each word, and check against what you want to find using equality "==" operator

Code:

awk '{
 for ( i=1;i<=NF;i++){
  if ( $(i) == "world"){
   print $0
  } 
 }
}
' file

what about grep -w :

Code:

     -w       Searches for the expression as a word  as  if  surrounded by \< and \>.

Code:

#  grep -w world infile
1 Hello world fantasy.
3 Hello world   wonderful.

thanks for the reply guys.