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Hi,

I think you ppl did not get my question correctly, let me explain

I have 1.txt with following entries as shown:

0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433
**
**
**

In file 2.txt I have the following entries as shown:

0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433
0789456|332211|10.20.30.40|078945633
1234567|225522|10.20.30.50|123456733
0321654|999999|10.20.30.40|032165433
0456123|777899|10.20.30.40|045612333
***
***
***

I want take the IP Address column from 1.txt and then search it in 2.txt and comment the duplicate entry from second matched pattern.

i.e., i need to have the following output in 2.txt as shown:

0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433
#0789456|332211|10.20.30.40|078945633
#1234567|225522|10.20.30.50|123456733
#0321654|999999|10.20.30.40|032165433
#0456123|777899|10.20.30.40|045612333
***
***
***

Below is the script i wrote but it will comment all the duplicate entries:

for i in `cat 1.txt |cut -d"|" -f3`
do
cat 2.txt |sed "s/^\(.*\|$i\|.*)/#/g" > tmp.txt
mv tmp.txt 2.txt
done

Can some one guide me how to leave the first duplicate entry untouched and comment from second duplicate entry and so on.

Please do not close this thread if you do not know the answer.

Thanks
-Imas

No duplicate or cross-posting, read the rules.

Proceed here:

https://www.unix.com/shell-programmin...#post302246044

Thread closed.