UNIX for Dummies Questions & Answers

Hi All
I have to encrypt files and add a suffix ".gpg_<key used>" to it
For example if the file name is test.dat after encryption the file name will be
test.dat.gpg_X005 (here X005 is the key).
I want to decrypt the file later using that key and the original file name.both of them should be picked up from the encrypted file name in unix file system.
The script i am using
echo "testfile1.dat.gpg_1EB85FB3" |awk 'BEGIN{FS=".gpg_"}{print $1}'
and getting the output as
testfile1
Where as I want the output to be
testfile1.dat

I think the field separator is not working properly when used as multicharacter.
Please help me writing the above script.

Code:

echo "testfile1.dat.gpg_1EB85FB3" |awk 'BEGIN{FS="."; OFS="."}{print $1,$2}'

Or with sed:

Code:

echo "testfile1.dat.gpg_1EB85FB3" | sed 's/\(.*\)\..*/\1/'

Thanks for your quick response.

I want the original file name and the key used for encryption. The file name and the key can be anything and it needs to be picked from the file specified for e.g. if the file name is

testfile1.dat.gpg_1EB85FB3

Then the original file name is testfile1.dat and the key is 1EB85FB3 . Is there a way I can distinguish it as two fields by taking .gpg_ as the fiels separator?

Thanks.

Code:

awk -F ".gpg_" '{print $1, $2}'

Regards

Hi Franklin-

Using the above command awk takes only . as the field separator and not the whole .gpg_.

Is there a way to provide multi character delimiter.

Regards,
Pradeep

Works fine for me, try nawk or gawk.

Regards