UNIX for Dummies Questions & Answers

Hi gurus,

I have set of files in a directory

ex : test_file1.csv
test_file2.csv
test_file3.csv

my requirement is to copy these files into another directory but with date appended to the name :

like after copying the files should look like : test_file1_07072008.csv
test_file2_07072008.csv
test_file3_07072008.csv

is this possible an di fpossible can we perform in a single unix command?

any help is apprecaited.

thanks

You can write something like this:

Code:

dt=$(date +%d%m%Y)
for f in *csv; do 
  mv "$f" another_directory/"${f%.csv}_$dt.csv"
done

thanks for the prompt response, is there nay other way of doing it

--like using in a single unix command line.

There are many ways of doing it, the question is why you don't want to use the one above ...

I'm using an ETL TOOL which takes an unix command with parmaeters, so i was looking at that method only.

What are the parametrs that you want to pass? Destination directory and filenames?

Yes. source directory ,destination directory and file pattern.