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grep XXX that not followed by YYY

 
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# 1  
Old 06-10-2008
grep XXX that not followed by YYY
I want to grep all lines containing blocking sess= that are not followed by 0x0
Code:
cat trace.log
blocking sess=0x0
blocking sess=0x0
rrrr......
blocking sess=121
blocking sess=0x0
blocking sess=0x0
blocking sess=0x0
some other lines
blocking sess=001
blocking sess=0x0
blocking sess=0x1

the grep output should be

Code:
blocking sess=121
blocking sess=001
blocking sess=0x1

any idea ?
Last edited by ynixon; 06-10-2008 at 10:26 AM..
# 2  
Old 06-10-2008
I seems that in your file you have only lines in the form "blocking sess=XxY"... So:

Code:
grep -v "blocking sess=0x0" trace.log

# 3  
Old 06-10-2008
Quote:
Originally Posted by robotronic
I seems that in your file you have only lines in the form "blocking sess=XxY"... So:

Code:
grep -v "blocking sess=0x0" trace.log

you are right, the example was wrong... I fixed the example see above
# 4  
Old 06-10-2008
grep -v "0x0" trace.log
# 5  
Old 06-10-2008
Go with the "dirty and simple way":

Code:
grep -v "blocking sess=0x0" trace.log | grep "blocking sess"

Or try something different:

Code:
awk -F"=" '/blocking sess=/ && $2 != "0x0"' trace.log

# 6  
Old 06-10-2008
With Sed:

Code:
sed -n '/=0x0/!{/blocking sess=/p;}' trace.log

Last edited by radoulov; 06-10-2008 at 11:02 AM..
# 7  
Old 06-10-2008
Quote:
Originally Posted by navi
grep -v "0x0" trace.log
This will not filter the lines with "rrrr......" and "some other lines" Smilie
 
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