removing a character and addending to end in each line in a file


 
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# 1  
Old 01-28-2008
removing a character and addending to end in each line in a file

HI i am having a file this

(sys19Smilienlfct:/pfact/temp>) cat temp_sand
1234567890
1234567890
1234567890
1234567890


I want to make this file as
(sys19Smilienlfct:/pfact/temp>) cat temp_sand
1456789023
1456789023
1456789023
1456789023


just take the 2nd and 3rd position and put it in end of ecah line . PLease let me know how to do that

Thanks,
Arun
# 2  
Old 01-28-2008
Code:
echo '1234567890' | sed 's/^\(.\)\(..\)\(.*\)/\1\3\2/'


Last edited by vgersh99; 01-28-2008 at 12:58 PM.. Reason: 2nd and 3rd (not 3rd and 4th)
# 3  
Old 01-28-2008
Code:
sed 's/^\([0-9]\)\([0-9]\{2\}\)\([0-9]*\)$/\1\3\2/' file

# 4  
Old 01-29-2008
Thanks all,

can you please let me know how it is done there . I have done the same by replacing the number it is not working.

echo '1234567890' | sed 's/^\(..\)\(..\)\(.*\)/\1\3\2/'

it is working but the same below is not working

echo '1234567890' | sed 's/^\(..\)\(..\)\(.*\)/\1\3\3/'

why it is not working ??.

Thanks in advance ,
Arunkumar
# 5  
Old 01-29-2008
It is giving you the right result albeit it may not be the result you want

Code:
$ echo '1234567890' | sed 's/^\(..\)\(..\)\(.*\)/\1\3\3/'
12567890567890

The first pattern, i.e. \1, is "12"
The second pattern, i.e. \2, is "34"
The third pattern, i.e. \3, is "567890"
# 6  
Old 01-30-2008
thanks ... I got into my head how it works Smilie
 
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