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how to execute a while loop for 20 minutes?

 
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# 1  
Old 07-05-2007
how to execute a while loop for 20 minutes?
I want to execute a while loop (or any other loop) for 20 minutes.

I have extracted the minutes and seconds from the current system date by using the command y = `date +%M%S`

How to proceed ??
# 2  
Old 07-05-2007
I would try something like
Code:
#! /usr/bin/ksh
secs=$(perl -e 'print time(), "\n"')
((targetsecs=secs+20*60))
while ((secs < targetsecs)) ; do
        sleep 5
        echo running
        secs=$(perl -e 'print time(), "\n"')
done
echo done
exit 0

# 3  
Old 07-05-2007
Is this a right approach?

Code:
#!/bin/ksh
SECONDS=0
while [[ SECONDS -lt 1200 ]] ; do
 echo $SECONDS
done

Thanks
nagarajan G
# 4  
Old 07-05-2007
Bug It worked for 20 minutes
Quote:
Originally Posted by Perderabo
I would try something like
Code:
#! /usr/bin/ksh
secs=$(perl -e 'print time(), "\n"')
((targetsecs=secs+20*60))
while ((secs < targetsecs)) ; do
        sleep 5
        echo running
        secs=$(perl -e 'print time(), "\n"')
done
echo done
exit 0


Thanx Perderabo !!!!!!!!!!!
# 5  
Old 07-05-2007
Quote:
Originally Posted by ennstate
Is this a right approach?

Code:
#!/bin/ksh
SECONDS=0
while [[ SECONDS -lt 1200 ]] ; do
 echo $SECONDS
done


It works if u r sure that 1 complete execution of the loop takes exactly 1 second. if the no. of statement is more then it may take more than a second to execute the loop once.
# 6  
Old 07-05-2007
Quote:
Originally Posted by ennstate
Is this a right approach?

Code:
#!/bin/ksh
SECONDS=0
while [[ SECONDS -lt 1200 ]] ; do
 echo $SECONDS
done

Thanks
nagarajan G
I like that solution better than mine because it does not need perl.
# 7  
Old 07-05-2007
Quote:
Originally Posted by subhotech
It works if u r sure that 1 complete execution of the loop takes exactly 1 second. if the no. of statement is more then it may take more than a second to execute the loop once.

It doesnot depend on the number of statements that are executed in the while loop.But it depends on the number of SECONDS spend since the shell invocation.

man ksh says,
Quote:
SECONDS
Each time this variable is referenced, the number of seconds since shell invocation is returned. If this variable is assigned a value, then the value returned upon reference will be the value that was assigned plus the number of seconds since the assignment.
Thanks
Nagarajan G
 
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