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Unix find command to print directory and search string

 
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# 1  
Old 03-06-2007
Unix find command to print directory and search string
Hi

i need to print pathname in which the string present using 'find' command


sample output like this


Pathname String to be searched
---------- --------------------
/usr/test/myfile get
/opt/test/somefile get



Thanks in advance
# 2  
Old 03-06-2007
not clear
Did you want to list the file that had the word 'get'. Is that the string you are referring to? Se if this works for you -
Code:
find /dir/from/where/you/want/to/search -type f -exec grep -l 'get' {} \; 2>/dev/null

# 3  
Old 03-06-2007
If you want to get the details of the file containing string 'string', you this

grep -ir 'string' /dir/from/where/you/want/to/search
# 4  
Old 03-06-2007
Hope u can use find with Xargs .. Will be the simple ways !!!!!!! Smilie
# 5  
Old 03-06-2007
Quote:
Originally Posted by ranj@chn
Did you want to list the file that had the word 'get'. Is that the string you are referring to? Se if this works for you -
Code:
find /dir/from/where/you/want/to/search -type f -exec grep -l 'get' {} \; 2>/dev/null

Thanks dude, its been ages that i've searched for that kind of command! Smilie
Knowing not the minus l option of grep, I used to
Code:
find /dir/from/where/you/want/to/search -type f -exec cmd.sh 'get' {} \;

where cmd.sh is
Code:
grep $1 $2 2>/dev/null
[ $? -eq 0 ] && echo $2

 
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