Need help in Regular Expression


 
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# 1  
Old 09-26-2006
Need help in Regular Expression

I have a file with data that looks like -

record nullable { final_delim=end ,delim="~%%~" ,quote=none }
(
1_UPC:string[13];
2_QUANTITY:string[7];
)

I want to fetch the first column that starts with integer. e.g - 1_UPC, 2_QUANTITY.

I tried "awk -F ":" -v var1="^0-9" '$1==var1' inschemafile". It is not recognising regular expression. What should I do to get the column?
Any help is appreciated.
# 2  
Old 09-26-2006
Code:
awk -v var="^[0-9]" ' $0 ~ var { sub( /:.*$/,"",$0); print }' file

== is for matching exact string
~ is for matching regular expression

or

Code:
sed -n "s/^\([0-9][^:]*\):.*/\1/p" ff

# 3  
Old 09-26-2006
Thanks a lot. It worked!!
 
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