UNIX for Dummies Questions & Answers

i have a snippet from server log delimited by forward slash.

/a/b/c/d/filename

i need to cut until last delimiter. So desired output should look like:

/a/b/c/d

can you please help?

Thanks in advance.

Is this a homework assignment?

What operating system are you using?

What shell are you using?

Not home work actually. Part of KT.
x86_64 GNU/Linux
bash shell.

Like so?

Code:

var=/a/b/c/d/filename
echo "${var%/*}"

If you want to get the pathname of the directory containing a file whose name is stored in a variable (as opposed to removing the last / and everything following it, consider this alternative:

Code:

var=/a/b/c/d/filename
echo "$(dirname "$var")"

With var set this way, you'll get the same results both ways (but dirname will run slower). But, compare the results of the above code with the code Scrutinizer suggested with these settings for var:

Code:

var=filename
var=/filename

Thanks.
Actually i am trying to generate a report from log.
I have awk'ed this field which is containing directory and filename altogether.
All I need is, to pass directory name and filename in 2 variable and put it under final report.

Show us the output you want, the input you have, and the program you've got. Should be possible to put it inside the awk program you have.