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sed Exact Match when Dot is present

 
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# 8  
Old 03-19-2015
Another technique:
add extra delimiters to the beginning and end,
then do a global substitution with delimiters attached and re-substituted,
then remove the extra delimiters.
Code:
echo "Bottle Bottle.Water Bottle Can" |
sed '
s/^/ /; s/$/ /
s/ Bottle /  /g
s/^ //; s/ $//
'

This User Gave Thanks to MadeInGermany For This Post:
Don Cragun
# 9  
Old 03-19-2015
How about (assuming your sed has EREs):
Code:
sed -E 's/Bottle([[:space:]]|$)//g' <<<"Bottle Bottle.Water Bottle Can Bottle"
Bottle.Water Can

# 10  
Old 03-19-2015
Quote:
Originally Posted by RudiC
How about (assuming your sed has EREs):
Code:
sed -E 's/Bottle([[:space:]]|$)//g' <<<"Bottle Bottle.Water Bottle Can Bottle"
Bottle.Water Can

That should then be:

Code:
sed -E 's/(^|[[:space:]])Bottle([[:space:]]|$)/\1\2/g' <<<"Bottle Bottle.Water Bottle Can Bottle"

Which is what Don was referring to in post #4

--
But a problem with these sed approaches is when there is foo Bottle Bottle bar, then it still does not work correctly, something that the awk approach avoids..

-- Edit: --
Perhaps this perl:
Code:
perl -pe 's/(^|(?<=\s))Bottle(?=(\s|$))//g'

Last edited by Scrutinizer; 03-19-2015 at 06:38 AM..
# 11  
Old 03-19-2015
The look-ahead is sufficient:
Code:
echo Bottle foo Bottle Bottle Bottle.Water bar Water.Bottle Bottle |
perl -pe 's/(^|\s)Bottle((?=\s)|$)/$1/g'

The $1 puts back a leading space (omit if not desired).
 
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