GREP function in ksh which ignores LINE Breaks


 
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# 8  
Old 09-20-2014
Hi.

A versatile member of the grep family, the non-standard cgrep, allows matches across newlines (among many other extended features, such as extracting windows of lines around matches). For example:
Code:
#!/usr/bin/env bash

# @(#) s1	Demonstrate match across lines, cgrep.
# For cgrep source, see:
# http://sourceforge.net/projects/cgrep/

# Utility functions: print-as-echo, print-line-with-visual-space, debug.
# export PATH="/usr/local/bin:/usr/bin:/bin"
LC_ALL=C ; LANG=C ; export LC_ALL LANG
pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C cgrep

FILE=${1-data1}

pl " Input data file $FILE:"
cat $FILE

pl " Results, cgrep for ST*82 to RITE AID across lines:"
cgrep -l -a 'ST\*82.*\n.*RITE AID' $FILE

exit 0

producing:
Code:
$ ./s1

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian 5.0.8 (lenny, workstation) 
bash GNU bash 3.2.39
cgrep ATT cgrep 8.15

-----
 Input data file data1:
ISA*00* 00 *ZZ*NATIONSBANK *14*0030020520500 *140918*1200*U*00401*000006436*0*P*^ 
GS*RA*014578892*IGIHCJEEJ*20140918*1200*6442*X*004010
ST*820*000006482 
N1*PR*RITE AID HDQTRS. CORP.*1*014578892

-----
 Results, cgrep for ST*82 to RITE AID across lines:
data1

The cgrep code usually needs to be obtained and compiled. I have done so on 32-bit and 64-bit systems without trouble. See the script comment for the source URL.

Best wishes ... cheers, drl
# 9  
Old 09-20-2014
Try:
Code:
awk 'FNR==1{p=1} /ST\*820/{p=0} !p && /RITE AID/{print FILENAME}' file(s)


--
On Solaris use /usr/xpg4/bin/awk rather than awk

Last edited by Scrutinizer; 09-20-2014 at 11:49 AM..
This User Gave Thanks to Scrutinizer For This Post:
# 10  
Old 09-20-2014
Hi.

For portability (but not performance), there is a perl version of grep, peg, that has many features, including the ability to use perl expressions and functions. The near functions allow one to look backwards from a line which matched a pattern, effectively matching across lines:
Code:
#!/usr/bin/env bash

# @(#) s2	Demonstrate match across lines, peg.
# For peg source, see:
# # http://www.cpan.org/authors/id/A/AD/ADAVIES/peg-3.10

# Utility functions: print-as-echo, print-line-with-visual-space, debug.
# export PATH="/usr/local/bin:/usr/bin:/bin"
LC_ALL=C ; LANG=C ; export LC_ALL LANG
pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C peg

FILE=${1-data1}

pl " Input data file $FILE:"
cat $FILE

pl " Results, peg for RITE AID back to ST*82 across lines:"
peg -l '/RITE AID/ and near(sub{/ST\*82/},-1)' $FILE

exit 0

producing:
Code:
$ ./s2

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian 5.0.8 (lenny, workstation) 
bash GNU bash 3.2.39
peg (local) 3.10

-----
 Input data file data1:
ISA*00* 00 *ZZ*NATIONSBANK *14*0030020520500 *140918*1200*U*00401*000006436*0*P*^ 
GS*RA*014578892*IGIHCJEEJ*20140918*1200*6442*X*004010
ST*820*000006482 
N1*PR*RITE AID HDQTRS. CORP.*1*014578892

-----
 Results, peg for RITE AID back to ST*82 across lines:
data1

The peg code has many of the same basic options as GNU grep, in addition to a number of extensions. For basic work on systems that do not have GNU grep it seems to be an acceptable substitute in many situations. The comment in the shell script points to the code source.

Best wishes ... cheers, drl
# 11  
Old 09-22-2014
Quote:
Originally Posted by Scrutinizer
Try:
Code:
awk 'FNR==1{p=1} /ST\*820/{p=0} !p && /RITE AID/{print FILENAME}' file(s)


--
On Solaris use /usr/xpg4/bin/awk rather than awk
I am using this command:-awk 'FNR==1{p=1} /ST\*820/{p=0} !p && /RITE AID/{print FILENAME}' natriter820u.20140914 but getting an error.
awk: syntax error near line 1
awk: bailing out near line 1

I am very new to this stuff so if you can please suggest what I am doing wrong here then it will be very helpful
# 12  
Old 09-22-2014
I don't suppose you tried my code too?
# 13  
Old 09-22-2014
Quote:
Originally Posted by Corona688
I don't suppose you tried my code too?
I did and with same syntax error, I think either I am missing something basic here or it is my system limitations.
Here is what I tried:-
Code:
awk -v P1="ST.820" -v P2="RITE AID"
# set A if P1 found, set B if P2 found
0~P1{A=1} $0~P2{B=1} 
# If filename changes, and A set, and B set, print filename.  Reset A and B.
(L != ARGIND) { L++; if(A && B) print ARGV[L];  A=B=0 }
# Check A and B for the last filename and print.
END { if(A&&B) print ARGV[L] }' /edi/editst/archive/sterling/in/*

and I got the same syntax error
# 14  
Old 09-22-2014
You are leaving out the single quotes, which totally changes the meaning of anything you do.

Put the single quotes back in and try again.
 
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