UNIX for Dummies Questions & Answers

As the title says I'm running a korn script in attempts to find an exact match in named.conf

finddomain.ksh

Code:

#!/bin/ksh
#
echo "********** named.conf ************"
file=/var/named/named.conf
for domain in `cat $1`
do
grep -n '"\$domain "' $file
done

echo "********** thezah.inc ***********"
file=/var/named/thezah.inc
for domain in `cat $1`
do
grep -n $domain $file
done

domains.txt

Code:

hosangit.com
djzah.com

In the named.conf or thezah.inc I'm looking for exactly "hosangit.com" not hosangit.com.br or site1.hosangit.com but just hosangit.com and the same thing goes for djzah.com

I'm running on a old SunOS server

I found running the following worked

Code:

/usr/bin/grep -i -n '"hosangit.com"' /var/named/named.conf

The issue is if I try and run a variable it won't work because of the single quote won't see the variable $domain

I also tried to breakout by putting a \ in front of $domain but still no luck so I'm hoping I could get a push in the right direction.

Thank you

---------- Post updated at 04:38 PM ---------- Previous update was at 04:26 PM ----------

I believe i figured it out

Code:

#!/bin/ksh
#
echo "*******named.conf**********************"
for domain in `cat $1`
do
file=/var/named/named.conf
grep -i -n '"'$domain'"' $file
done

fgrep treats a dot like a normal character, and variables should always be in quotes

Code:

fgrep -i -n \""$domain"\" $file

And the variable file should be defined once, before the loop.