get a file date/timestamp


 
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# 1  
Old 12-21-2005
get a file date/timestamp

Could someone tell me how to get the date/time (to the second) a file was last modified? I need to know if a file was modified in the last 30 seconds from the system date. I'm on AIX/unix 4.3
# 2  
Old 12-21-2005
Code:
#!/usr/bin/perl

#^ PROGRAM DESCRIPTION
#^ -------------------
#^ This program prints the modification times and names of files.
#^ It uses the following format:  inodetime.pl filename
#^ It will accept:  inodetime.pl filename1 filename2 filename3
#^                  inodetime.pl /tmp/file*
#^ The format of the output is: YYYYMMDDhhmmss filename
#^ example:
#^           $ inodetime.pl /tmp/t*
#^           19961115105425 /tmp/test.sql
#^           19970116113616 /tmp/tststat.pl
#^
#^###################################################################

# Get the (next) input from the command line
while ($curfile = $ARGV[0])
{
# Do following code block only if $curfile exists
   if (-e $curfile)
   {
# stat structure into variables
      ($dev,$ino,$mode,$nlink,$uid,$gid,$rdev,$size,
      $atime,$mtime,$ctime,$blksize,$blocks) = stat("$curfile");
# time structure into variables
      local($sec,$min,$hr,$day,$mon,$yr,$wday,@dntcare) = localtime($mtime);
      $yr = ($yr>=70) ? $yr+1900 : $yr+2000;
      $yr="$yr";
      $mon = (++$mon < 10) ? "0$mon" : "$mon";
      $day = ($day < 10) ? "0$day" : "$day";
      $hr  = ($hr < 10) ? "0$hr" : "$hr";
      $min = ($min < 10) ? "0$min" : "$min";
      $sec = ($sec < 10) ? "0$sec" : "$sec";
# Rearrange in the YYYYMMDDhhmmss format and assign to $dte variable
      $dte = join('',$yr,$mon,$day,$hr,$min,$sec);
      # Print modification date and filename
      print ("$dte $curfile\n");
   }
# Shift to next position in command line
   shift (@ARGV);
}

# 3  
Old 12-21-2005
Time in seconds since a file was last modified...
Code:
perl -e '@q=stat($ARGV[0]); print time-$q[9]' file1

# 4  
Old 12-22-2005
just what i needed! Thanks a lot to you both
 
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