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Lists in awk

 
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# 1  
Old 09-19-2013
Lists in awk
Hi togehter!

I would like to write an awk script which prints the first column divided by the sum of the second column:

So if this is my list

Code:
1 2
2 1
3 1
4 1

it should print a list like this:

Code:
1/5
2/5
3/5
4/5

My idea was to use END like this:

Code:
 awk '{sum+=$2;} END {print $1/sum}'

But it doesnt work... can someone help me?

Thanks!!
# 2  
Old 09-19-2013
Code:
$ awk 'NR==FNR{a+=$2;next}{print $1"/"a}' file file
1/5
2/5
3/5
4/5

This User Gave Thanks to pamu For This Post:
bjoern456
# 3  
Old 09-19-2013
Code:
awk '{sum+=$2;a[++i]=$1} END{for (i in a) {print a[i]"/"sum}}'  infile

This User Gave Thanks to krishmaths For This Post:
bjoern456
# 4  
Old 09-19-2013
Quote:
Originally Posted by krishmaths
Code:
awk '{sum+=$2;a[++i]=$1} END{for (i in a) {print a[i]"/"sum}}'  infile

The for-in-loop should not be used. The OP wants to preserve the order of the list, buti in a is not guaranteed to preserve order.
Code:
awk '{sum+=$2; a[NR]=$1} END{for (i=1; i<=NR; i++) {print a[i]"/"sum}}'  infile

Regards,
Alister
Last edited by alister; 09-19-2013 at 12:21 PM..
These 2 Users Gave Thanks to alister For This Post:
bjoern456 krishmaths
 
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