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[Solved] Find position of character with awk

 
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Top Forums UNIX for Dummies Questions & Answers [Solved] Find position of character with awk
# 1  
Old 08-19-2013
[Solved] Find position of character with awk
Hi Guys!
Could anyone help me with?..
I have a line which says

BCVGF%6$#900 .....How can we know which position is for % or say $ by command or script?There is any way to get a prompt by any script?

Thanks a lot
# 2  
Old 08-19-2013
Code:
echo "BCVGF%6$#900" | awk '{for(i=1;i<=length($0);i++) {if (substr($0,i,1)=="%") {print i}}}'

This User Gave Thanks to krishmaths For This Post:
Indra2011
# 3  
Old 08-19-2013
Thanks a lot Krish!!!!!
# 4  
Old 08-19-2013
Yet another way with awk...
Code:
echo "BCVGF%6$#900" | awk -F% '{print length($1)+1}'

# 5  
Old 08-19-2013
Code:
echo 'BCVGF%6$#900' | awk '{print index($0,"%")}'

Returns 0 if not found.
# 6  
Old 08-19-2013
Code:
T=${LINE%%\%*}; echo $((${#T}+1))

Returns length(LINE) +1 if not found
# 7  
Old 08-20-2013
Thanks every one of you for the help!!!!

Moderator's Comments:
Mod Comment edit by bakunin: changed thread title accordingly
Last edited by bakunin; 08-20-2013 at 07:46 AM..
 
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