display a portion of lines from file


 
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# 1  
Old 09-20-2005
display a portion of lines from file

This is truly dummy question.

I have a text file of 100 lines.

What unix commnad to extract line 20 to 40 and output it to another file?

Is it something cat or grep or >> ?

Thanks
# 2  
Old 09-20-2005
Code:
sed -n '20,40p' input.file > output.file

vino

Last edited by vino; 09-20-2005 at 12:41 AM..
# 3  
Old 09-20-2005
MySQL

sed -n '20,40p' infile > outfile
# 4  
Old 09-20-2005
just another way of doing it

awk '{if (NR >= 20 && NR <= 40) print $0}' inputfile > outputfile
# 5  
Old 09-20-2005
While we are exploring different ways of doing things:
Code:
 head -40 infile|tail -20 > outfile

# 6  
Old 09-20-2005
Quote:
Originally Posted by blowtorch
While we are exploring different ways of doing things:
Indeed Smilie

Code:
perl -n -e  '( $. >= 20 && $. <= 40 ) && print ' infile > outfile

Cheers
ZB
# 7  
Old 09-20-2005
Quote:
Originally Posted by matrixmadhan
just another way of doing it

awk '{if (NR >= 20 && NR <= 40) print $0}' inputfile > outputfile
or more concisely
Code:
awk 'NR >= 20 && NR <= 40' infile > outfile

or more quickly on a large file:
Code:
awk 'NR >= 20; NR == 40 {exit}' infile > outfile


Last edited by reborg; 09-20-2005 at 12:12 PM.. Reason: fix the tags
 
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