Help with find command


 
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# 1  
Old 02-06-2013
Help with find command

Hi,
Im a newbie.All your suggestions needed.
Im developing a script that should that find dat files based on the file name(file name is created has date info) after comparing it with the current timestamp.Let me put it in a clear way.
For instance,
Say I have files say like
Code:
AA_XX_20121208    /*date part in name of the file*/
AA_XX_20121207
AA_XX_20121206
AA_XX_20121205
AA_XX_20121204
AA_XX_20121203
AA_XX_20130108
AA_XX_20130107
AA_XX_20130106
AA_XX_20130105
AA_XX_20130104
AA_XX_20130103
AA_XX_20130208
AA_XX_20130207
AA_XX_20130206
AA_XX_20130205
AA_XX_20130204
AA_XX_20130203

.
.
.so onFor e.g. this month is February,
the script must find all files relating to January and December.Similarly during month of March,
i must fetch files of January and February. This has to happen each month .

Please note,i do not want to find files based on the modified timestamp (find . -name 'AA_XX_*' -mtime -60)Smilie,
but using the name of the file which has date part.

Thanks in advance,
MJK
# 2  
Old 02-06-2013
It seems a little twisted, but it works:
Code:
YEAR=`date +%Y`
MONTH=`date +%m`
MONTH1=$(( MONTH - 1 ))
YEAR1=$YEAR
if [[ $MONTH1 -eq 0 ]]
then
MONTH1=12
YEAR1=$(( YEAR - 1 ))
fi
MONTH2=$(( MONTH1 - 1 ))
YEAR2=$YEAR1
if [[ $MONTH2 -eq 0 ]]
then
MONTH2=12
YEAR2=$(( YEAR1 - 1 ))
fi
PATTERN1=`printf "AA_XX_%s%02d" $YEAR1 $MONTH1`
PATTERN2=`printf "AA_XX_%s%02d" $YEAR2 $MONTH2`
find . -name $PATTERN1\*
find . -name $PATTERN2\*

# 3  
Old 02-08-2013
Thanks a lot franzpizzo !!
# 4  
Old 02-08-2013
Quote:
Originally Posted by franzpizzo
It seems a little twisted, but it works
Another sh-based alternative:
Code:
read m y <<EOF
$(date +'%m %Y')
EOF

read m1 y1 m2 y2 <<EOF
$(((m-1+11)%12+1)) $([ $m -eq 1 ] && y=$((y-1)); echo $y) \
$(((m-1+10)%12+1)) $([ $m -lt 3 ] && y=$((y-1)); echo $y)
EOF

# m1/y1 is the month/year of one month ago
# m2/y2 is the month/year of two months ago.

Regards,
Alister

Last edited by alister; 02-08-2013 at 02:21 PM..
 
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