Simple bash script menu


 
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# 1  
Old 01-13-2013
Simple bash script menu

Dear Sir,

May I know how do I go about adding the following feature into the script below:

When user enter values other than 1,2,3,4,

a) Message “Wrong entry !!! Pls select 1,2,3 or 4” is displayed
b) The screen is cleared again and the menu is displayed.


Code:
#!/bin/bash
clear
var=1
until [ $var -eq 4 ] 
do
echo "Menu"
echo "(1) Item 1"
echo "(2) Item 2"
echo "(3) Item 3"
echo "(4) Exit"
read -p "Enter your choice " var
clear
echo "Your choice is $var"
done

I've tried adding * but it returns an syntax error.

Thank you.

Last edited by Scrutinizer; 01-13-2013 at 05:43 AM.. Reason: code tags
# 2  
Old 01-13-2013
Hope this helps

Hi Fusetrips,
Try using the below its off one of the scripts I already have built.

Code:
*) echo "Please select a valid choice ";
echo "Press a key to return to the menu. . ." ; read ;;
esac
:
done


to the user running the script it looks like the below

Code:
Enter your menu choice:
30
Please select a valid choice
Press a key to return to the menu. . .

once a key has been pressed it returns to the menu

Last edited by Scrutinizer; 01-13-2013 at 05:47 AM.. Reason: code tags
# 3  
Old 01-13-2013
Try using a case statement or an if statement.
 
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