awk - output field separator


 
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# 1  
Old 01-06-2013
awk - output field separator

In awk, how do I print all fields with a specified output field separator?

I have tried the following, which does not print the output FS:

Code:
echo a b c d | awk 'BEGIN{OFS = ";"}{print $0}'

# 2  
Old 01-06-2013
You'll need to either print the fields one by one or force the reconstruction of the record:
Code:
zsh-5.0.0[]% echo a b c d | awk 'BEGIN { OFS = ";" }{ print $1, $2, $3, $4 }'
a;b;c;d
zsh-5.0.0[]% echo a b c d | awk 'BEGIN { OFS = ";" } { $1 = $1; print }'     
a;b;c;d

Assigning a value to a field causes the reconstruction of the current record,
as you only need to change the output format, you may use the $n = $n idiom.
These 2 Users Gave Thanks to radoulov For This Post:
# 3  
Old 01-06-2013
Thanks radoulov! The reconstruction of the record solution was new to me.
# 4  
Old 01-06-2013
Using AWK gsub function to substitute OFS

Code:
echo a b c d | awk '{gsub(OFS,";")}1'
a;b;c;d

 
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