Question on grep


 
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# 1  
Old 01-02-2013
Question on grep

Hello all,

I'm trying to grep the string "scott" from all files whose names are like srvr*.log and that were created "Nov 15"...I'm trying the following command but throws an error message...seems like the syntax is incorrect..
Code:
grep scott < ls -l srvr*.log|grep "Nov 15"

Thanks for your time..

Last edited by joeyg; 01-02-2013 at 12:25 PM.. Reason: Please wrap commands and data with CodeTags
# 2  
Old 01-02-2013
Need more info

Are you looking for "scott" to be part of the name of a file, or text inside the file?
# 3  
Old 01-02-2013
I'm looking for the string "scott" inside the files srvr*.log that got created on Nov 15.
# 4  
Old 01-02-2013
Try this:
Code:
touch --date "2012-11-14" start
touch --date "2012-11-16" end

find -type f -newer start -not -newer end -name "srvr*.log" -exec grep "scott" {} \;

find version:
Code:
GNU find version 4.2.27

This User Gave Thanks to Yoda For This Post:
# 5  
Old 01-02-2013
Thanks for the quick response. Appreciate your help...It works but is there any other way to do it without "touching" the start and end files?

Thanks
# 6  
Old 01-02-2013
Code:
find . -type f -mtime $(( ( $(date +%s) - $(date -d '2012-11-15' +%s) ) / 60 / 60 / 24 - 1 )) -name "srvr*.log" -exec grep "scott" {} \;

# 7  
Old 01-02-2013
Try this
Code:
grep "scott" srvr*.log  |grep "Nov 15"

 
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