UNIX for Dummies Questions & Answers

Hi ,

i am beginner to Unix, I have one small script which execute java programme,it has java command input output structure . Right now i have given Input output structure manually that is on same directory, now how can i pass that by commandline

#!/bin/sh

java Classjava input.txt output.xml output.structure

How can i pass variable parameter from command line.

Thanks

sam70

#!/bin/sh

java Classjava $1 output.xml output.structure

Now that $1 will be replaced by the first command line argument. You can use $2, $3, etc as well.

Hi ,

I have tried putting $1 $2 but it doesnt work

Thanks

sam70

Can you copy and paste the results?

Hi ,

Here is message

Usage: TFFtoXML <output.xml> <input.flat> <input.ffd> [logfile]


this is java command to be executed on shell script. this output we see when
we execute this on command line in local machine.it is a .bat file and we do
ff2xml and enter then it gives this information as above which i see when i put $1 $2 . But it not asking for variable input.

THanks

sam70

It won't ask for variable input. It will behave the way you requested in your first post. Remember this? "How can i pass variable parameter from command line."

That script is in a file. The file has a name. Somehow you invoke the script by name. Let's say that you named the script "fred". You might use:
fred
./fred
/some/path/to/fred
when you run it. That is the command line. Put a space after fred. Type another word. That word will be $1 inside the script.
./fred input.txt