Name directories with "0s"


 
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# 1  
Old 10-11-2012
Name directories with "0s"

Hi everyone,

I want to create 4000 directories with names like dir0001 ... dir 0100 till dir4000 and move 100 files in each.

I am using this :
Code:
ls|xargs -n100|awk ' {i++;system("mkdir dir"i);system("mv "$0" -t dir"i)}'

I get the directory names at dir1, dir2 etc. which is not good for later sorting of directories.

Thanks.

Moderator's Comments:
Mod Comment Please use code tags next time for your code and data.

Last edited by vbe; 10-11-2012 at 09:36 AM..
# 2  
Old 10-11-2012
try something like this..


Code:
  for i in {1..1000}
 do
 dir_name=$(printf "%04d" "$i")
 mkdir "$dir_name"
 mv files "$dir_name"
 done


Last edited by pamu; 10-11-2012 at 10:12 AM.. Reason: corrected after elixir's advise..:)
# 3  
Old 10-11-2012
Quote:
Originally Posted by pamu
try something like this..


Code:
 for i in {1..1000}
 do
 dir_name=$(echo $i | awk '{ printf "%04d",$0}{print ""}')
 mkdir "$dir_name"
 mv files "$dir_name"
 done

You forget that there is an external command/shell built-in called printf, too.
So, that's a useless use of awk. Smilie

Last edited by elixir_sinari; 10-11-2012 at 10:11 AM..
# 4  
Old 10-11-2012
Quote:
Originally Posted by elixir_sinari
You forget that there is an external command/shell built-in called printf, too.
So, that's a useless use of awk. Smilie
Yeah. Thanks...
edited in original post. Smilie
This might be the first time useless use of awk...Smilie
# 5  
Old 10-11-2012
Thanks for all replies !!
# 6  
Old 10-12-2012
Quote:
Originally Posted by pamu
try something like this..


Code:
  for i in {1..1000}
 do
 dir_name=$(printf "%04d" "$i")
 mkdir "$dir_name"
 mv files "$dir_name"
 done

Need to add dir in the printf

Code:
 
printf "dir%04d" "$i"

 
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