UNIX for Dummies Questions & Answers

I have the below script I am running on a Solaris system to check the status of a Tivoli Workload Scheduler job and return the status. We need this script to return a '0' if any of the jobs in the stream are in a "EXEC" state and an "1" if in a "HOLD" state. I am not a programmer so I am not sure if this ist he correct way to script what I am looking for.
When I run this script I get no output which I want to get from the awk statement. The exit status is always a "0" as well.
Any help would be appreciated. Thanks

set RETURNCODE1=1
set RETURNCODE2=0

cd /usr/local/Tivoli/maestro/scripts/bin

#OUTPUT=`/usr/local/Tivoli/maestro/bin/conman sj cawlki11#adsfctacbrds_dly@+stat
e=HOLD`
#OUTPUT=`/usr/local/Tivoli/maestro/bin/conman sj cawlki11#adsfctacbrds_dly@+stat
e=EXEC`
STATE=echo ${OUTPUT} | awk '{ print $17 }'`

if [ "${STATE}" = "HOLD" ]
then
$RETURNCODE2
else
$RETURNCODE1
fi

try this:

Code:

#!/bin/ksh
RETURNCODE1=1
RETURNCODE2=0

cd /usr/local/Tivoli/maestro/scripts/bin

#OUTPUT=`/usr/local/Tivoli/maestro/bin/conman sj cawlki11#adsfctacbrds_dly@+stat
e=HOLD`
#OUTPUT=`/usr/local/Tivoli/maestro/bin/conman sj cawlki11#adsfctacbrds_dly@+stat
e=EXEC`
STATE=$(echo "${OUTPUT}" | awk '{ print $17 }')

if [ "${STATE}" = "HOLD" ]
then
   exit "${RETURNCODE2}"
else
   exit "${RETURNCODE1}"
fi