UNIX for Dummies Questions & Answers

Hi all,

Could someone please explain to me the shell invocation process when running a script. How do I stop the shell from logging out when it reaches an exit statement in the script?

Code:

        if [ $? -ne 0 ]; then
                echo 'Failed to copy ${FILE}.fmx to ${J2_HOME}/dev/rsc'
                exit 1
        fi

This is inside a function called publish_form. I want to execute the command from the command line like publish_form form1.fmx but every time it hits the exit statement in the function def, the shell exits and my unix session ends.

Help is appreciated?

Thanks.

Rich.

I don't exactly understand what you're doing, but try changing the "exit 1" to "return 1".

remove 'exit' from the script and try.

Thanks that's solved it.