converting string to number in shell script


 
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# 1  
Old 02-22-2012
Question converting string to number in shell script

Hi,

I am having a problem in converting a string to number so I can preform arithmetic operations.

timeTot=0
timeTmp=$(cat idsOutput | grep 'Run time' | cut -c 36-39)
timeTot=$[$timeTot+$timeTmp] #This is line 28
echo "total RunTime=" $timeTot


this is the error msg:

./ids2.sh: line 28: 0+1.35: syntax error: invalid arithmetic operator (error token is ".35")
total RunTime= 0
# 2  
Old 02-22-2012
Quote:
Originally Posted by turki_00
cat idsOutput | grep 'Run time'
Please post the output of cat idsOutput | grep 'Run time'
# 3  
Old 02-22-2012
cat idsOutput

Commencing packet processing (pid=2103)
===============================================================================
Run time for packet processing was 1.3579 seconds
# 4  
Old 02-22-2012
Code:
#!/bin/bash
timeTot=0
timeTmp=$(grep 'Run time' input | cut -c36-39)
timeTot=`echo "$timeTot + $timeTmp" | bc`
echo "total RunTime=" $timeTot

# 5  
Old 02-22-2012
Code:
$ echo "0 + `awk '/Run time/ {print $7}' idsOutput`" | bc
1.3579
$ echo "10 + `awk '/Run time/ {print $7}' idsOutput`" | bc
11.3579

# 6  
Old 02-22-2012
Try .. in your script ..
Code:
timeTot=`echo "$timeTot + $timeTmp" | bc`; echo "total RunTime=" $timeTot

--Shirish Shukla
# 7  
Old 02-22-2012
Thank you balajesuri
it works

However, I am doing this code inside a loop and then taking the average (avgT).
but the output of avgT is the integer part of the solution
I tried to use the bc method for the average but it only giving me the integer part of the solution.


Here is my code:
Code:
#!/bin/bash
myLoop=$1
i=1
timeTot=0

while [ $i -le $myLoop ]
do
timeTmp=$(grep 'Run time' input | cut -c36-39)
timeTot=`echo "$timeTot + $timeTmp" | bc`
i=$[$i+1]
done

echo "total RunTime=" $timeTot
avgT=`echo "$timeTot / $myLoop" | bc`
echo "Average RunTime=" $avgT

the output
Code:
./ids2.sh 2
total RunTime= 2.85
Average RunTime= 1

the value of Average RunTime should be = 2.85/2 = 1.425
 
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