UNIX for Dummies Questions & Answers

I would need a command for finding first 15000 of the file names whose 25th postion is 5 in the current directory alone.


I do have this painful command

find . -name '[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]5*' | head -15000 | cut -c3-

please refine this.

Of course the above command also searches in the sub directories which I dont want.

please dont use 'maxdepth' since it would not work on my unix.

appreciate your help!

Code:

find . | egrep '^.{24}5' | head ...

You can just use "ls" to search only in the current directory.

one more ..

Code:

$ ls -ltr | grep -v ^d | awk '{print $9}' | sed '/^.\{24\}5/!d'

Thank u for your help

My files naming convention would be as below. When I use the following command its listing out both naming conventon files. I just need the list of files of first type alone.
ls | egrep '^.{21}8' | head -15000

3914850220110830173809000437activityLog.txt
laatws74_9_aLog_20110830225437_1.txt

can you plz help me on this