UNIX for Dummies Questions & Answers

Hi,

when I echo the values of two variables that have been set for example:

export FRUIT1=ORANGE
export FRUIT2=APPLE

echo $FRUIT1
ORANGE

echo $FRUIT2
APPLE

as expected but when I echo the following:
echo ${FRUIT1}AND{$FRUIT2}

I was expecting to get:
ORANGEANDAPPLE

but instead am getting:
APPLEEAND

So my FRUIT1 value is being partly overwritten instead. Why would this occur?

The environment I am using is SUSE Linux Enterprise Server 11 with the Korn shell (apologies if I need to give more specifics of my environment as I am not currently at work).

Regards,
Jaxim

Code:

#  echo ${FRUIT1}AND{$FRUIT2}
echo ${FRUIT1}AND${FRUIT2}

$ in the wrong place

Apologies for the typo on my part, Jim. I did try this earlier today at work with:
echo ${FRUIT1}AND${FRUIT2}
and I still got output of:
APPLEEAND

I tested it on my system and it does work properly displaying:

Code:

ORANGEANDAPPLE

Can you show your current script with the "${" change?

Hi,

Here is the script I have been using to test:

Code:

#!/bin/ksh

export FRUIT1=ORANGE
export FRUIT2=APPLE

echo $FRUIT1
echo $FRUIT2
echo ${FRUIT1}AND${FRUIT2}

Works fine for me on Solaris. Try quoting the last line:

Code:

echo "${FRUIT1}AND${FRUIT2}"

or try using print instead of echo.

Seems you have a carriage return in your output. From the look of it, it's emitted just before "APPLE". If so, after printing "ORANGE, the carriage return, \r, would cause the cursor to return to column 1. Then the first five letters of "APPLE" would overwrite the first five letters of "ORANGE", leaving the final "E" and the word "AND" afterwards.

You can test my hypothesis by filtering your echo through tr:

Code:

echo ${FRUIT1}AND${FRUIT2} | tr -d \\r

---------- Post updated at 09:55 AM ---------- Previous update was at 09:46 AM ----------


If that tr corrects your output, I'd check for a carriage return in the two spots in your code where I inserted the bold, red "\r".

Regards,
Alister