Area of a square


 
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# 1  
Old 07-22-2010
Area of a square

I am just starting out with bash scripting. I tried a simple script to find the area of a square and it didnt run.
Code:
#!/bin/bash
#script to find area of a square based on user input

if [ $# -ne 1 ]
then 
   echo " Usage -$0 x "
   echo " where x is the dimension of the square "
   exit 1
   n1=$1

echo " Area of the square is equal to `expr $n1 * $n1` "

I know its supposed to be simple but someone shed light on whats wrong.

Moderator's Comments:
Mod Comment Use code tags please, ty.
# 2  
Old 07-22-2010
You are missing a fi to close the if.
# 3  
Old 07-22-2010
And the "*" in the expr needs escaping as "\*".

Code:
#!/bin/bash
#script to find area of a square based on user input

if [ $# -ne 1 ]
then 
   echo " Usage -$0 x "
   echo " where x is the dimension of the square "
   exit 1
fi
n1=$1
echo " Area of the square is equal to `expr $n1 \* $n1` "

 
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