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How to cut a string in two parts and show the other part

 
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# 1  
Old 05-26-2010
Question How to cut a string in two parts and show the other part
hi everybody..

I have a string like :

abcd:efgh
xxyy:yyxx
ssddf:kjlioi
ghtyu:jkksk
nhjkk:heuiiue

please tell me how i can display only the characters after ":" in the output

the output should be :
efgh
yyxx
kjlioi
jkksk
heuiiue

please give quick reply.. its urgent..!!
thanx..
# 2  
Old 05-26-2010
Code:
cut -d":" -f2 file

Code:
sed "s/.*://" file

Code:
awk -F":" '  {print $2} ' file

# 3  
Old 05-26-2010
Code:
while IFS=: read dump field; do echo $field; done < input.txt
cut -d: -f2 input.txt
sed -e 's/^.*://' input.txt
awk -F: '{print $2}' input.txt

# 4  
Old 05-26-2010
Code:
perl -F: -ane 'print $F[1]' infile

# 5  
Old 05-27-2010
Quote:
Originally Posted by pseudocoder
Code:
perl -F: -ane 'print $F[1]' infile

I am using this here as follows
Code:
perl -F: -ane 'print $F[0]'  < /etc/passwd | sort | xargs echo

but due to absence of newline char in between the results, I am not getting the output as expected. If I use '\n' inside print (in single quotes) error is throwing up. If I surround the print field in double quotes I am getting weird output. How to solve it?
Last edited by royalibrahim; 05-28-2010 at 06:13 AM..
# 6  
Old 05-27-2010
Change
Code:
perl -F: -ane 'print $F[0]'  < /etc/passwd | sort | xargs echo

to
Code:
perl -F: -alne 'print $F[0]'  < /etc/passwd | sort | xargs echo

The -l switch will automatically remove newlines from input and add it to output.
# 7  
Old 05-27-2010
resultingstring=$(echo $string | cut -d":" -f2)


say string="sumthing:nothing"

resultingstring will have "nothing".
 
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