error in for loop???


 
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# 1  
Old 01-12-2010
error in for loop???

Hi,
I get the following output
Code:
98 -1
98 0
./get_AB04-time: line 79: ((: i< && 0 !=7 : syntax error: operand expected (error token is "&& 0 !=7 ")

I have this part of code. Line 79 is the line of the for loop.

Code:
        echo ${OCCURRENCE[$J]} $i_START
        CASE=0;
        i_END[$J]=${i_START}
        for (( i=${i_START};i<$OCCURRENCE && ${CASE} !=${5} ;i++)); do
        ...
        done

The echoed values are correct, it seems the code has a problem with the for loop and I can't figure out why.

Also $i_START instead of ${i_START} gives the same error.
Can anybody help?
Thank you,
Sarah
# 2  
Old 01-12-2010
What shell are you using - i.e., bash, ksh, etc. -
Code:
echo $SHELL

will tell you.
# 3  
Old 01-13-2010
/bin/bash
# 4  
Old 01-13-2010
Is $OCCURENCE and array? Because you're using it as one in line 76, and as a regular variable in line 79, and the shell apparently can't substitute that, leading to an empty operand in the condition part of the for loop.
# 5  
Old 01-13-2010
Yes, thanks a lot a spent hours on it and I just couldn't see it.
Now I have,
Code:
        for (( i=${i_START};i<${OCCURRENCE[$J]} && ${CASE} !=${5} ;i++)); do

 
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