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if statement code syntax

 
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# 1  
Old 01-07-2010
if statement code syntax
Hi, can someone please tell me what is wrong with this code? I just want it to check if the file size is greater than 2000kb.

Code:
if [ du -sk $FILE -gt 2000 ]

Thanks!

---------- Post updated at 09:23 PM ---------- Previous update was at 09:21 PM ----------

I should probably post the full code:

Code:
#!/bin/sh
#Daniel Heidt's program to sort archive shots into folders by document markers

filecount=1
mkdir $filecount

for FILE in DSC*
do
     if [ $FILE != "test.sh" ]
	then
		if [ du -sk $FILE -gt 2000 ] #dumps file into existing $filecount folder - will later be used if image is not marker
		  then
		  echo $FILE
		  mv "$FILE" "$filecount"
		else #bumps filecount - will later be used to skip over marker shots
		  let filecount=filecount+1
		  mkdir $filecount
		fi
     fi
done

# 2  
Old 01-07-2010
Try using back ticks around your command that you want to execute:

if [ `du -sk $FILE` -gt 2000 ]
# 3  
Old 01-07-2010
Good suggestion - but I'm still getting the same error: "[: too many arguments"

Other suggestions? Am I trying to do too much in one if statement? Should I perhaps read the result of "du -sk $FILE" into a variable and then compare it within the if statement?
# 4  
Old 01-07-2010
Try running the du command by itself from the command line. I'm thinking it might be outputting something more than just an interger. If so then that's why it's unable to compare it with another interger and so the test fails.

If the output is more spitting out more than just a number, then you might want to pipe it through awk to get the field you need. I would suggest assigning the output to a variable and then using that in your test statement. Let me know what happens.
# 5  
Old 01-08-2010
Try this

Code:
if [ `du -sk $FILE` -gt 2000 ];then

# 6  
Old 01-10-2010
Hi you're right, I'm not getting a simple integer readout. I'm getting this:

Code:
$ du dsc03143.jpg
3784	dsc03143.jpg

I am extremely unfamiliar with the awk command and haven't been able to find a tutorial that makes much sense to me yet. Can anyone help me out with isolating the integer so that it can be compared? I know its a simple string isolation but I can't figure out how to do it. Or is there an easier way to only get the number?
# 7  
Old 01-10-2010
Code:
$ du dsc03143.jpg | awk '{print $1}'

# so...
if [ $(du dsc03143.jpg | awk '{print $1}') -gt 2000 ]; then

Last edited by Scott; 01-10-2010 at 07:49 PM..
 
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