UNIX for Dummies Questions & Answers

Hello,
I'm trying to do a list of user that never connected to a couple of servers. I want to do a diff between the servers lists, and print out only the users that never has logged on each server. Here my first step :

SERVER01:
# finger `egrep -v -e "^\s*#" /etc/passwd | awk '{ print $1 }' | sort | uniq` | grep og > login_server01
# perl -n -e ' if ( m/Never/ ) { print $aa.$_ }; $aa =$_ ' < login_server01> never_server01

SERVER02:
# finger `egrep -v -e "^\s*#" /etc/passwd | awk '{ print $1 }' | sort | uniq` | grep og > login_server02
# perl -n -e ' if ( m/Never/ ) { print $aa.$_ }; $aa =$_ ' < login_server02> never_server02

now... how to make a merge between the two files?

really thanks
br

Interesting...

I would have thought people not in login_server file:

Code:

last| sort|cut -d" " -f1|uniq >login_server

would be people never connected (and so compared with users in /etc/passwd)

yes, it's quite logic...
thanks

Hey, wait there,
You are giving up to fast! Iwas only trying to find another complicated way to accomplish the given task...
Your reasoning was valid, but lack of practice... finger gives you all you need, you just had to figure out how to use it
To make it easy I put in script form rather than a one-liner:

Code:

cat /etc/passwd|cut -d: -f1|sort|uniq |while read USER
do
NEVER=$(finger $USER|grep Never)
 if [ "$NEVER" != "" ]
 then
    echo $USER" "$NEVER
 fi
done

Replacing the cat /etc/passwd... by a true users list would be far better (no daemons or other accounts in...)

Thanks, here the last code. Now a diff between the two servers is a little bit easy

Code:

egrep -v  -e "^\s*#" ./allowed | awk '{ print $1 }' | sort | uniq | while read USER
do
NEVER=$(finger $USER|grep Never)
 if [ "$NEVER" != "" ]
 then
    echo $USER" "$NEVER
 fi
done

br