UNIX for Dummies Questions & Answers

I have a file named filelist. the content is a list of files including the path.

$ cat filelist
$curdir/test1
$curdir/test2

I want to cat each file in the list, such as cat $curdir/test1, cat $curdir/test2. (The $curdir has been exported).

it can't open the test1/test2, it can't change $curdir to /home/steven/curdir in script, but I can run it on command line.

313$ cat $curdir/test
dfsfdfdsdffsfest
314$ cat `head -1 filelist`
cat: cannot open $curdir/test
315$ head -1 filelist
$curdir/test
316$

how to export the $curdir, so that cat can get it?

Perhaps...

Code:

#!/bin/sh

TESTDIR=/var/tmp
export TESTDIR

file=`cat $TESTDIR/filelist`
for i in $file 
do
    cat $i
done

Thanks your reply
what's the content of your $TESTDIR/filelist?

I mean the file $TESTDIR/filelist also include some relative path.

such as (all realtvie path are set in .profile)

$TESTDIR/test1
$TESTDIR/test2
$TESTDIR2/test3

I just had /var/tmp/test1 and /var/tmp/test2 in my /var/tmp/filelist file.