Data Pivot

 
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# 1  
Old 08-15-2017
Data Pivot

Good Day,

I have file input
Code:
6285296582710|20170509|INDOTEL
6285296835209|20170509|INDOTEL
6285296940311|20170509|INDOTEL
6285297027737|20170509|MULTIFLAG
6285297027737|20170509|DELTA
6285297304373|20170510|INDOTEL
6285297384129|20170510|INDOTEL
6285296940311|20170510|MULTIFLAG
6285297542691|20170516|AXES

I need to print $1 in $1 and $2 as header in horizontal then put $3

output
Code:
MSISDN|20170509|20170510|20170516
6285296582710|INDOTEL||
6285296835209|INDOTEL||
6285296940311|INDOTEL|MULTIFLAG|
6285297027737|MULTIFLAG,DELTA||
6285297304373||INDOTEL|
6285297384129||INDOTEL|
6285297542691|||AXES

Thanks
# 2  
Old 08-15-2017
This is as unspecific a specification as can be. DON'T have people guessing what you want! Why should anybody care more for the problem than you do?
Where does the term "MSISDN" come from?

And, with quite some membership time and 139 posts, you should at least have some vague idea on how to tackle this problem. So - any attempts / ideas / thought from your side?
This User Gave Thanks to RudiC For This Post:
# 3  
Old 08-19-2017
It is a pity there was no follow-up, you really learn a lot more if you post your attempts..

Anyway, here is an example of what a solution might look like:

Code:
awk '
  NR==FNR {
    A[$1,$2]=A[$1,$2] (A[$1,$2]?",":"") $3
    B[$1]
    if (!($2 in H)) {
      h=h OFS $2
      H[$2]=c++
    } 
    next
  }

  FNR==1 {
    print "MSISDN" h
  } 

  $1 in B {
    for(i in H)
      $(H[i]+2)=A[$1,i]
    print
    delete B[$1]
  }
' FS=\| OFS=\| file file

Code:
MSISDN|20170509|20170510|20170516
6285296582710|INDOTEL||
6285296835209|INDOTEL||
6285296940311|INDOTEL|MULTIFLAG|
6285297027737|MULTIFLAG,DELTA||
6285297304373||INDOTEL|
6285297384129||INDOTEL|
6285297542691|||AXES

--
Note: the file name needs to be specified twice so that it gets read twice..
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