Awk or Sed help


 
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# 1  
Old 04-02-2008
Awk or Sed help

Hi,

I have a data file with 5 columns - like this:

"20080401 09:43:08.770798 +0100s","TEST 1","R 1","A TEST","Nov 27 2007","1"
"20080401 09:43:08.770798 +0100s","THIS IS A TEST","R 2","B TEST","Nov 30 2007","10"
"20080401 09:43:08.770798 +0100s","ANOTHER TEST","R 3","B TEST","Nov 05 2007","14"

I would like to delete the last two values e.g. ,"Nov 05 2007","14"

How can I do this using sed or awk?

Many Thanks!
# 2  
Old 04-02-2008
With sed you can something like:

Code:
sed '/$/s/,"Nov 05 2007","14"//' file

Regards
# 3  
Old 04-02-2008
Quote:
Originally Posted by Franklin52
With sed you can something like:

Code:
sed '/$/s/,"Nov 05 2007","14"//' file

Regards
Thanks for your reply - this will not work for me as the values in the last two columns could differ.
# 4  
Old 04-02-2008
try:
Code:
awk -F, '{print $1","$2","$3","$4}' file

# 5  
Old 04-02-2008
Ok, try this one:

Code:
awk '
BEGIN{FS=OFS=","}
s{print s}
{printf("%s,%s,%s,%s", $1,$2,$3,$4);s=","$5 ","$6}
END{print ""} 
' file

Edit:

Maybe I'm missing something, but i assumed you want to delete the 2 last columns of the last line.
If you want to delete the last 2 columns on every line you can use the code of unilover.


Regards
# 6  
Old 04-02-2008
Quote:
Originally Posted by unilover
try:
Code:
awk -F, '{print $1","$2","$3","$4}' file

Thank you, this is good, however, two questions.

I have added this to my sed script but I get this error when I run sed -f (script) - "sed: command garbled: awk -F, '{print $1","$2","$3","$4}'"

Also, when I run your command I get ,,, (three commas) at the end of each line.
# 7  
Old 04-02-2008
Well, what I wrote IS a complete UNIX-Command which, obvously and naturally, SHOULD be executed either from a Command-Line or in a SHELL-SCRIPT!!!

as for the "three-commas", you should definitely be messing up something or your data-file is not exactly as you'd said is!?!?!
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