UNIX for Advanced & Expert Users

I am doing "ps -f" to see my process.
but I get lines that one of it represents the ps command itself.
I want to grep it out using -v flag, but than I get another process that belongs to the GREP itself :

I would like to exclude

[root@localhost ~]# ps -f
UID PID PPID C STIME TTY TIME CMD
root 15794 15792 0 13:48 pts/2 00:00:00 -bash
root 16157 15794 0 14:01 pts/2 00:00:00 ps -f

[root@localhost ~]# ps -f | grep -v ps
UID PID PPID C STIME TTY TIME CMD
root 15794 15792 0 13:48 pts/2 00:00:00 -bash
root 16160 15794 0 14:02 pts/2 00:00:00 -bash

while all I want is to get my pid line only.
or maybe you know another command that returns my pid and ppid only ?

thanks

how 'bout

Code:

echo "myPID->[$$] PPID->[$PPID]"

or for Bourne shell (courtesy of USENET comp.unix.shell):

Code:

echo "myPID->[$$] PPID->[`ps -o ppid= -p $$`]"

I wonder ,Which flavor of Unix you use ? in the following example it is working:

Code:

[root@dns ~]# uname -a
Linux dns 2.6.22.5-76.fc7 #1 SMP Thu Aug 30 13:47:21 EDT 2007 i686 athlon i386 GNU/Linux
[root@dns ~]# ps -f | grep -v ps
UID        PID  PPID  C STIME TTY          TIME CMD
root      2593  2572  0 Oct04 pts/1    00:00:00 -bash

also works in HP Unix,
can you check this out:

[root@dns ~]# ps -f | grep -v ps |grep -v grep
UID PID PPID C STIME TTY TIME CMD
root 2593 2572 0 Oct04 pts/1 00:00:00 -bash