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Help In Awk

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# 1  
Old 09-21-2006
Lightbulb Help In Awk
Hi Friends,
I need a help again in awk.
I just need to round up a value.

Eg Say x=5.664584525
I need to display x=5.66 means round. How can i do round in UNIX.
# 2  
Old 09-21-2006
Use the printf format "%.2f" to perform rounding.
e.g.
echo "5.664584525" | awk '{printf "%.2f",$0}'
output will be 5.66
Last edited by Dhruva; 09-21-2006 at 07:23 AM.. Reason: example given
# 3  
Old 09-21-2006
Quote:
Originally Posted by Dhruva
Use the printf format "%.2f" to perform rounding.
e.g.
echo "5.664584525" | awk '{printf "%.2f",$0}'
output will be 5.66

Thanks a load
Dhruva..

Its working fine ......Actually I was trying to do with round function and its was becoming really complicated... now its so simple.. Thanks dude..
# 4  
Old 09-24-2006
Hi Friends ,
I am again facing a problem there when I am trying to get the rouind of a fraction.
Say X = 8/3
It should give the value as 2.66

So please can give any inputs ...

Thanks In Advance...
# 5  
Old 09-24-2006
Help in to get a round value.
Hi Friends,

Can any one please give the following solution.

Say I have a variable x = 8/3

I need the value of x as 2.66.

And I am using the same in shell script.

Can I get the above value with round function or awk command.


Thanks in advance friends.
# 6  
Old 09-24-2006
8/3 = 2.666666... rounded to 2 decimals is normally 2.67
Code:
b = `echo "8/3" | bc -l`
printf ".2f\n" $b

printf does rounding for you
# 7  
Old 09-24-2006
Through shell?
Code:
echo "scale=2; 8/3"|bc

Soumya Dash, please do not post in multiple threads on the same topic. I have merged the threads.
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