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Resume parent shell after sourcing another script

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# 1  
Old 02-03-2017
Resume parent shell after sourcing another script
Code:
#! /bin/ksh
#first.sh
echo "b4 set exit as return"
alias exit=return
echo "call second"
. ./second.sh
echo "after second"

#. ./third.sh
unalias exit
echo "ho lanciato il terzo"

=================//

Code:
#second.sh
echo "in scond"
exit

==============//

the above code works in k shell, but not works in bash, how to write the same in bash..
Last edited by Scrutinizer; 02-03-2017 at 04:11 AM.. Reason: code tags
# 2  
Old 02-03-2017
Your exit in second.sh causes first.sh to terminate because it's all the same shell. Remove that and it would run fine.

I don't think that the alias exit=return will be effective, but it is very confusing nonetheless.


I get this output when run with the trace option:-
Code:
$ bash -x first.sh
+ echo 'b4 set exit as return'
b4 set exit as return
+ alias exit=return
+ echo 'call second'
call second
+ . ./second.sh
++ echo 'in scond'
in scond
++ exit

Oddly, it seems to work in ksh:-
Code:
$ ksh -x first.sh
+ echo 'b4 set exit as return'
b4 set exit as return
+ alias exit=return
+ echo 'call second'
call second
+ . ./second.sh
+ echo 'in scond'
in scond
+ return
+ echo 'after second'
after second


I hope that this helps,
Robin
Last edited by rbatte1; 02-03-2017 at 04:55 AM.. Reason: Added trace output.
# 3  
Old 02-04-2017
bash by default does not expand aliases in non-interactive shells..

Try something like this:
Code:
shopt -s expand_aliases 2>/dev/null
echo "b4 set exit as return"
alias exit=return

Then it should run in either shell
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