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# 1  
Old 09-08-2015
awk command help
Hi all,

could you please help me understanding following awk command.

Code:
awk 'c&&c--;/^61,67/ {c=5}' filename.txt

What will it do and how ?

Thanks
# 2  
Old 09-08-2015
Hello brij123,

Following may help you in same.
Code:
awk 'c&&c--;/^61,67/ {c=5}' filename.txt
It is searching a line in a file which starts from 61,67 if that is the case with any line then we are setting value of variable named c=5.
Now c&&c-- means c(if variable c is NOT equal to 0, c-- means if variable's value is not null)
then do default action which is print in awk.
So ultimately aim is to print lines once we match a line which starts from 61,67 and print next 5 lines.

Hope this helps.


Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
brij123
# 3  
Old 09-08-2015
What will be the syntax if I want to print everything other than those 5 lines ?
# 4  
Old 09-08-2015
Hello brij123,

Could you please try following and let me know if this helps. It will not print even the line which has starting from 61,67.
Code:
awk '/^61,67/{c=5};{if(c>=0){c--;next}};{print}'  Input_file

EDIT: If you want to print that line which has string starting with 61,67 and NOT to print next 5 lines then following may be helpful for you.
Code:
 awk '/^61,67/{c=5;print};{if(c>=0){c--;next}};{print}'  Input_file

Thanks,
R. Singh
Last edited by RavinderSingh13; 09-08-2015 at 06:39 AM.. Reason: Added a note for solution now
This User Gave Thanks to RavinderSingh13 For This Post:
brij123
# 5  
Old 09-08-2015
Great .. Thanks Smilie
# 6  
Old 09-08-2015
Try also
Code:
awk '/^61,67/ {L=NR+5} NR >= L' file

This User Gave Thanks to RudiC For This Post:
brij123
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