Grep lines accordingly


 
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# 1  
Old 08-24-2015
Grep lines accordingly

Hi Guys,
I need help..
I have 2 files with some lines the script will grep lines available in file1 with file2 & prints if a line is missing on file2
Code:
#!/bin/bash
set -x
while read path
do
egrep $path file2
if [ `echo $?` != 0 ];then
echo "path $path is missing " >> output
fi
done < file1

Code:
more file1
/dell/sony/power/IS/server
/dell/sony/power/IS/
/dell/sony/power/
/dell/sony/
/dell/
/dev/testcase failing

more file2
/dell/sony/power/IS/server
/dell/sony/power/IS/
/dell/sony/power/
/dell/

I m getting the wrong OUTPUT:
Code:
path /dev/testcase failing is missing

output should be like >
Code:
path /dev/testcasefor/failing  is missing 
path /dell/sony/ is missing


Last edited by vbe; 08-24-2015 at 01:41 PM.. Reason: please use code tags for your code and data
# 2  
Old 08-24-2015
Code:
awk '{arr[$0]++}       
       END {for (i in arr){if(arr[i]<2 ){print i, " is missing"}} } ' file1  file2 > error_listing

awk may be a better choice. Try something like the above.
This User Gave Thanks to jim mcnamara For This Post:
# 3  
Old 08-24-2015
The output is correct, /dev/sony is present. The grep command will match any part of a line that matches. You probably want to use the -w flag for exact word search.
Padow
# 4  
Old 08-24-2015
Hi.

If you allow exact, entire line matches:
Code:
$ fgrep -x -v -f z9 z8
/dell/sony/
/dev/testcase failing

Because /dell can match a number of strings.
Code:
       -x, --line-regexp
              Select only those matches that exactly match the whole line.
-- excerpt from man fgrep

Best wishes ... cheers, drl
This User Gave Thanks to drl For This Post:
# 5  
Old 08-24-2015
Hi,
For fun (under linux for "xargs"):
Code:
$ sort file1 file2 file2 | uniq -u | xargs -IXX echo path XX is missing 
path /dell/sony/ is missing
path /dev/testcase failing is missing

Regards.
This User Gave Thanks to disedorgue For This Post:
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