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To print from the first line until pattern is matched

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# 1  
Old 02-11-2015
To print from the first line until pattern is matched
Hi I want to print the line until pattern is matched.

I am using below code:

Code:
sed -n '1,/pattern / p' file

It is working fine for me , but its not working for exact match.

Code:
sed -n '1,/^LAC$/ p' file

Input:
Code:
LACC	FEGHRA		0
LACC	FACAF		0
LACC	DARA		0
LACC	TALAC		0
LAC 	ILACTC		0
LACC	Kerzner		0
LAAS	TOTAL		0
LACC	LAC		0
LACC	IRSI		0
LACC	Asocianes CTO	0
LACC	Kerzner		0

Expected Output:
Code:
LACC	FEGHRA		0
LACC	FACAF		0
LACC	DARA		0
LACC	TALAC		0
LAC 	ILACTC		0

# 2  
Old 02-11-2015
That is because $ would match end of line and not end of string. Depending on the exact nature of the input you could match for space/tab instead, or just not a letter:

Code:
sed -n '1,/^LAC[^a-zA-Z]/p' file

This User Gave Thanks to Walter Misar For This Post:
Abhisrajput
# 3  
Old 02-11-2015
Quote:
Originally Posted by Walter Misar
That is because $ would match end of line and not end of string. Depending on the exact nature of the input you could match for space/tab instead, or just not a letter:

Code:
sed -n '1,/^LAC[^a-zA-Z]/p' file


And if the Input is like below:
Code:
LACC	FEGHRA		0
LACC	FACAF		0
LACC	DARA		0
LACC	TALAC		0
LACC 	ILACTC		0
LACC	Kerzner		0
LAAS	TOTAL		0
LACC	LAC		0
LACC	IRSI		0
LACC	Asocianes CTO	0
LACC	Kerzner		0

Then Can I achive the below output:

Code:
LACC	FEGHRA		0
LACC	FACAF		0
LACC	DARA		0
LACC	TALAC		0
LACC 	ILACTC		0
LACC	Kerzner		0
LAAS	TOTAL		0
LACC	LAC		0

Thank you
# 4  
Old 02-11-2015
Although this
Code:
sed -n '1,/    LAC/p' file

will work with the sample given, try this
Code:
sed -rn '1,/^[^         ]+[     ]+LAC[  ]+/p' file

to be on the safe side (within the square brackets, there's a space and a <TAB> char). If your sed doesn't support the -r (or -E) option, replace the + with \+.
This User Gave Thanks to RudiC For This Post:
Abhisrajput
# 5  
Old 02-11-2015
Hi,
with gnu sed, we can use begin mark and end mark word:
Code:
sed -n '1,/\<LAC\>/p' file

Regards.
# 6  
Old 02-11-2015
Code:
sed -n '1,/\<LAC\>/p' file

This doesn't work for me.

Only the below code is working.

Code:
sed -n '1,/    LAC/p' file

# 7  
Old 02-11-2015
Ok, then a posix solution:
Code:
sed -n '1,/[^[:alnum:]_]LAC[^[:alnum:]_]/p' file

PS: posix definiton of word class is [A-Za-z0-9_]

Regards.
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