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problem using pipes with "ls"

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# 1  
Old 09-22-2009
Tools problem using pipes with "ls"
Hi all,

I tried the following command

$ find / -name xyx | ls -l

so logically it should show the listing of directory xyz , assuming there's only one instance of xyz . But the above command shows the listing of current directory instead.

I got the desired result using it in the following maner

$ find / -name xyx | xargs ls -l

so, the confusion is why do I need xargs here
# 2  
Old 09-22-2009
Hi!
That is because ls does not operate on standard input - you have to feed it standard input as an argument - that's why you use xargs.
# 3  
Old 10-06-2009
if you want use xargs
Code:
find / -name XYZ -type f | xargs -iINCLUDE ls -l INCLUDE

or

Code:
find / -name XYZ -type f -exec ls -l {} \;

# 4  
Old 10-06-2009
Code:
find . -ls

# 5  
Old 10-12-2009
1} So Many bways to to the same thing
2) In UNIX very often, the simplest way is already programmed
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