Quick Question

catbad · #1 (**permalink**) 03-22-2003

Hello There!
I am trying to write this SIMPLE script in Bourne Shell but I keep on getting syntax errors. Can you see what I am doing wrong? I've done this before but I don't see the difference. I am simply trying to take the day of the week from our system and when the teachers sign on I want them to see the message of the day, when they exe "Schedule" (the name of this script).

Code:

#!/bin/sh
case $day in

 Mon) echo '1st grade please meet in front office conference rm at 2 pm.';;
 Tue) echo 'No school for students';;
 Wed) echo 'Kindegarten, Jane will meet you in Saban's room.';;
 Thu) echo 'Short Faculty meeting in Media Center.';;

 Fri) echo 'Please remind parents to sign in at front office!';;
 Sat) echo 'If you are on VPDN, please be sure to logout';;
 Sun) echo 'Why are you working?, Its Sunday!';;
#
#
esac

added code tags for readability --oombera

oombera · #2 (**permalink**) 03-23-2003

Are you sure you use the words 'Mon' 'Tues' etc and not numbers that represent the day of the week?

1) echo '1st grade ...
2) echo 'No school ...
3) echo 'Kindergarten ...
...
...

catbad · #3 (**permalink**) 03-23-2003

Thanks for your help. I did change the days to numbers Sunday being one since that is the day our system starts. It did get rid of the syntax error BUT now when I run the script....nothing happens. Any additional ideas. My script now looks like this:

Code:

case $day in
 1) echo 'why are you working';;
 2) echo 'comment 2';;
 3) echo 'comment 3.';;
 4) echo 'comment 4/reminder.';;
 5) echo 'comment6.';;
 6) echo 'meetings?';;
 7) echo 'vpdn reminders';;
esac

added code tags for readability --oombera

oombera · #4 (**permalink**) 03-23-2003

Oh wait, $day is the day of the month, which means it'd be equal to 23 today... you want to use the variable $dayweek, where 0 represents Sunday, 1 is Monday, and so on.

Code:

# SHELL VARIABLES:
# ----------------
#
# YEAR    :  Year of the session to be processed (2 digit)
# DAYYEAR :  Julian day of the year
# DAY     :  Day of the Month
# MONTH   :  Month, 1=JAN, 12=DEC
# DAYWEEK :  Day of the week, 0=SUN, 6=SAT

http://www.unavco.ucar.edu/data_supp...k_scripts.html

catbad · #5 (**permalink**) 03-23-2003

Thank you for the link oombera. I do apprecite your help. I changed to dayweek and renumbered but I amstill not getting an outcome. I will do some research on the website you provided.

Thanks

Perderabo · #6 (**permalink**) 03-24-2003

I don't understand why you guys think that variables like WEEKDAY are set automatically. Even if that is true, $WEEKDAY and $weekday are two different variables.

Do something like this:
echo WEEKDAY = $WEEKDAY
to see if WEEKDAY is really set automatically in your environment. But I'm betting that it is just empty.

If you want to set a variable to the day of the week, do something like this:
weekday=`date +%u`

oombera · #7 (**permalink**) 03-24-2003

oops lol - magic variables that just know what you'd like them to contain and then set themselves

looks like s93366 got it right in the other thread.

More UNIX and Linux Forum Topics You Might Find Helpful
Thread	Thread Starter	Forum	Replies	Last Post
Help with AWK -- quick question	Probos	Shell Programming and Scripting	5	07-18-2007 04:26 PM
quick question	keith.m	AIX	5	12-21-2006 09:27 AM
quick sed question	vbm	Shell Programming and Scripting	2	11-09-2006 10:44 PM
quick question	pkolishetty	UNIX for Dummies Questions & Answers	2	09-02-2006 11:56 AM
Ok quick question	Corrail	Shell Programming and Scripting	1	11-11-2005 01:49 PM

Thread Tools	Search this Thread
Show Printable Version Email this Page	Search this Thread: Advanced Search
Display Modes	Rate This Thread
Switch to Linear Mode Hybrid Mode Switch to Threaded Mode	Rate This Thread: