Hi,
I am new to Unix and there is code that is trying to get data from a location and save it. However it's output is messing up some date fields in the source file (ie... in source is may say 10/10/2008, the code will output 10/10/20088). This is the piece of code. Can someone help to understand what it does and how it can be fixed? Thanks in advance!

#!/bin/ksh
#set final file
REPORT="/sas02/logistics/prom/incoming/LCL_KIT2_RPT.txt"
REPSRV="lcl####.ngco.com"
# using telnet through the http port 80 get the current name of the lcl promo file
REPURL=`(sleep 1; echo "GET /kixprod/cgi-bin/biceps_exec_log.pl?day=0 HTTP/1.0"; echo""; sleep 1) | telnet $REPSRV 80 | sed '/GROCERY.PROMOS/!d; s/.*ngco.com//; s/">.*//'`
#echo $REPURL
[[ -r $REPORT ]] && rm $REPORT
# using telnet through the http port 80 get the LCL_GROCERY_PROMO.txt file
(sleep 1; echo "GET $REPURL HTTP/1.0"; echo "Content-type: text/plain"; echo ""; sleep 60) | telnet $REPSRV 80 | sed "/,/!d; s/<.*>//; s/\&amp;/\&/; s/\&quot;/\q/" > $REPORT

mpinto,

I don't see any date in the piece of code you've provided. If your saying that it is appending the code 10/10/20088. Im recommending that you analyze your script and look for a function or script pertaining to date or appending to a date.

Cheers,

Can you show complete lines of input and output data?
My 2nd thought (after expecting a date command or obvoius data usage) is that one of the sed commands is duplicating the text.