Hi,

I want to list all the last directories from mentioned base path.

for eg: If i have a base path say /base/base1/

How can i get the path till last node in tree like directory structure of unix by applying any command.
so that i will get following output.

/base/base1/base2/final1/final2/last
/base/base1/base2/final1/final3/last
/base/base1/base2/final1/last
/base/base1/base2/final1/final4/last

find /base/base1 -type d -name "last" -print

In short i want all the possible unique longest paths under base dir

Its not necessary the last node is always "last"

Did you try it out at least? Or do I misunderstand

root@isau02:/data/tmp/testfeld> find bla -type d -print
bla
bla/yoyo
bla/yoyo/last
bla/yoyo/last/some
root@isau02:/data/tmp/testfeld> find bla -type d -name last -print
bla/yoyo/last
root@isau02:/data/tmp/testfeld>

In the above directory structure mentioned by you I want only "bla/yoyo/last/some" to be printed.

i.e The longest unique path. Here the last node is "some". I hope it clears now.

A directory with no subdirectories contains only two directories "." and "..".

#!/bin/ksh
find /base/base1/ -type d -print|sort|while read DIR
do
        DIR_COUNT=`ls -la "${DIR}"|grep \^d|wc -l`
        if [ ${DIR_COUNT} -eq 2 ]
        then
                echo "${DIR}"
        fi
done