Replace in VI

preethgideon · #1 (**permalink**) 11-26-2008

Hi All,
How to add a '*' at the begining of VI file between lines in a range say 20 -30??

Please help.

I tried :%s/20,30/^/\*/

Did not work.

Thanks and Regards,
Gideon.

radoulov · #2 (**permalink**) 11-26-2008

Code:

:20,30s/^/\*/

Yogesh Sawant · #3 (**permalink**) 11-27-2008

using Perl:

Code:

perl -pi -e 's/^/\*/  if ($. > 19  and  $. < 31);' /foo/bar

FlyingSquirrel · #4 (**permalink**) 11-27-2008

Why count lines, use markers instead.

1) Go to the 1st line in range and type in
ma

2) Go to the last line in range and type in
mb

3) Then do the substitution
:'a,'b s/^/*/

More UNIX and Linux Forum Topics You Might Find Helpful
Thread	Thread Starter	Forum	Replies	Last Post
replace last / by \|	naikaa	Shell Programming and Scripting	6	01-17-2008 02:19 AM
using sed to replace ' with `	mr_dba01	Shell Programming and Scripting	2	08-08-2007 08:24 AM
How to replace ??	preethgideon	UNIX for Dummies Questions & Answers	10	02-19-2007 12:08 PM
Replace \n with \r\n	Chanakya.m	Shell Programming and Scripting	3	07-19-2006 07:20 AM
what to replace XP with?	byblyk	Linux	2	05-23-2005 07:46 PM

Thread Tools	Search this Thread
Show Printable Version Email this Page	Search this Thread: Advanced Search
Display Modes	Rate This Thread
Linear Mode Switch to Hybrid Mode Switch to Threaded Mode	Rate This Thread: