Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.
|
Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.
|
|
google unix.com
|
|||||||
| Forums | Register | Forum Rules | Links | Albums | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
 |
| UNIX for Dummies Questions & Answers If you're not sure where to post a UNIX or Linux question, post it here. All UNIX and Linux newbies welcome !! |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Can somebody solve this please | sreenusola | Shell Programming and Scripting | 1 | 08-28-2008 07:50 PM |
| please help me solve this issue......... | Renjesh | SUN Solaris | 5 | 05-23-2008 08:28 AM |
| Help me to solve this issue | Renjesh | SUN Solaris | 2 | 05-09-2008 08:23 AM |
| Can AWK solve it ??? | emon | Shell Programming and Scripting | 1 | 02-23-2005 01:07 PM |
Powered by 
|
|
|
LinkBack | Thread Tools | Search this Thread | Rate Thread | Display Modes |
11-26-2008
|
||||
|
||||
Can anyone solve this awk issue ?
awk -F^ '{ if (($1 != "X") && ($5 != "3")) || if (($1 != "S") && ($5 != "2")) print $0}' abc> xyz
The above command returns this error awk: syntax error near line 1 awk: illegal statement near line 1 I am newbie to awk, Any awk intelligence involved in correcting this issue is highly appreciated. Thanks in advance. |
| Bookmarks |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|
Threaded Mode
