Can anyone solve this awk issue ?

karthickrn · #1 (**permalink**) 11-26-2008

awk -F^ '{ if (($1 != "X") && ($5 != "3")) || if (($1 != "S") && ($5 != "2")) print $0}' abc> xyz

The above command returns this error

awk: syntax error near line 1
awk: illegal statement near line 1

I am newbie to awk, Any awk intelligence involved in correcting this issue is highly appreciated.

Thanks in advance.

Franklin52 · #2 (**permalink**) 11-26-2008

Remove the second if in your awk command.

Regards

vguleria · #3 (**permalink**) 11-26-2008

Suggested usage:

awk -F^ '{ if ( (($1 != "X") && ($5 != "3")) || (($1 != "S") && ($5 != "2")) ) print $0}' abc> xyz

Regards,
Vinod.

Quote:

Originally Posted by karthickrn

awk -F^ '{ if (($1 != "X") && ($5 != "3")) || if (($1 != "S") && ($5 != "2")) print $0}' abc> xyz

The above command returns this error

awk: syntax error near line 1
awk: illegal statement near line 1

I am newbie to awk, Any awk intelligence involved in correcting this issue is highly appreciated.

Thanks in advance.

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