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11-25-2008
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get the latest file by reading the date in the filename.
Hi,
I grep for a pattern in a list of files. "grep -i -l $pattern *.datx*" it may give me n number of files. say for eg, it gives me 2 files. lock_eicu_20071228_00000000.dat_20071228_05343100 lock_eicu_20080501_00000000.dat_20080501_05343900 out of these 2 files I need to get the latest file according to the date present after the .dat extn. As 20071228 is older than 20080501, i need to get the second file. so in the above eg, i need to get the filename lock_eicu_20080501_00000000.dat_20080501_05343900 can u please help. |
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